Alternatively, you can use the isdigit() method to check if the entered number is a digit or not, and the final way is to use try/except to handle the unknown errors. Python: Python Questions: Invalid literal for int() with base 10. To solve the error, you can use the float() method to convert entered decimal input and then use the int() method to convert your number to an integer. ValueError: invalid literal for int() with base 10 occurs when you convert the string or decimal or characters values not formatted as an integer. Solution 3: The other common way to handle this kind of errors is using try except number= input("What is your weight:")Įrror - Please enter a proper weight Conclusion Print("Error - Please enter a proper weight") This problem happens because Python stores the input as. In other words its either empty, or has a character in it other than a digit. Python has isdigit() method, which returns true in case of a numeric value and false if it’s non-numeric. This error can frequently occur when converting user-input to an integer-type using the int() function. The error message invalid literal for int() with base 10would seem to indicate that you are passing a string thats not an integer to the int() function. So better way to solve this is to ensure the entered input is a numeric digit or not. Solution 2: There can be other possible issues where the entered input value itself might be in the string, so converting the string value will throw a Value Error even if we use the above method. Solution 1: We can first convert the input number into a float using float() method, parse the decimal digits, and convert them again into an integer, as shown below. Therefore it can only convert the string representation of int, not the decimal or float or chars. The int() function uses the decimal number system as base conversion, meaning base=10 is the default value for transformation.
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One can think that while executing the above code, Python will automatically truncate the decimal value and retain only the integer part. If we pass non-integer value as a string, it will generate value error in python invalid literal for int() with base 10. ValueError: invalid literal for int() with base 10: '55.5' ValueError: invalid literal for int() with base 10 occurs when you convert the string or decimal or characters values not formatted as an integer. With Python3.x, the same gives you ('1.5'): ValueError: invalid literal for int() with base 10: '1.5'. With Python2.x, int(str(3/2)) gives you '1'.
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Print ("The weight of the person is:" + str(kilos))įile "c:\Projects\Tryouts\listindexerror.py", line 2, in Sometimes the difference between Python2.x and Python3.x that leads to this ValueError: invalid literal for int() with base 10.